21.7 ML of gas at 98.8 K PA is allowed to expand at constant temperature in to a 52.7 mL container

40.68kPa

Explanation:

The remaining part of the question is requesting to calculate the pressure (p2) after increase in volume.

Data;

V1 = 21.3mL

P1 = 98.8 kPa

V2 = 52.7 mL

P2 = ?

Using Boyle's law,

PV = K

P1V1 = P2V2

98.8 * 21.7 = p2 * 52.7

P2 = 2143.96 / 52.7

P2 = 40.68 kPa

Note I didn't convert the values since they all have the same unit.

state the principle of separating two immiscible liquids by separating funnel. describe an activity with diagram to separate a mixture of water and kerosene oil. answer: immiscible layers separate out in layers depending on their densities in separating funne

it's all four options.