Calculate the number of moles of solute present and the number of grams
6.00 Liters of 3.00 M KCL

The answer is: 18 moles and 1341, 72 grams of KCl

Explanation:

The molarity is defined as the moles of solute ( in this case KCl) in 1 liter of solution:

1L solution3 moles of KCl

6L solutionx= (6L solutionx 3 moles of KCl)/1 L solution= 18 moles of KCl

We calculate the weight of 1 mol of KCl:

Weight 1 mol KCl= Weight K + Weight Cl= 39,09 g + 35, 45 g=74, 54 g/mol

1 mol KCl 74, 54 g

18 mol KClx= (18 mol KCl x 74, 54 g)/1 mol KCl=1341, 72 g

2b2t

explanation:

2b2t