A sample of a compound of Cl and O reacts with an excess of H2 to give 0.233g of HCl and 0.403g of H2O. Determine the empirical formula of the compound

Cl2O7

Explanation:

Molar mass of HCl= 36.5gmol-1

Molar mass of water =18gmol-1

To get the ratio of chlorine present in the original substance

0.233/36.5= 0.00638

To get ratio of oxygen present in the original compound

0.403/18= 0.0224

Then divide through by the lowest ratio

Cl- 0.00638/0.00638 O- 0.0224/0.00638

Cl- 1 O- 3.5

Multiplying through by 2 to give whole numbers

Cl-2. O-7

Hence the empirical formula of the compound is Cl2O7

they are both synthetic elements

explanation:

d

a saline water is fed to a reverse osmosis unit at flow rate o rotameter connected to reject (retentate) line reads 8 installed in reject and permeate line reads 15.2 milli siemens/cm and 300 micro siemens/com respectively.