125 grams of solid sodium hydroxide is combined with an excess of aqueous hydrochloric acid. The heat of neutralization for the formation of water -55.9 kJ/mole. The heat of solvation (it might be called the heat of solution) for sodium hydroxide is 41.0 kJ/mole What quantity of heat is released?

303 kilo Joules is the quantity of heat is released.

Explanation:

Moles of NaOH =

According to recation 1 mole of NaOh gives 1 Mole of water, then 3.125 moles of NaOH will give ;

of water

The heat of neutralization for the formation of water = -55.9 kJ/mol

Heat evolved on formation of 3.125 moles of water : Q

The heat of solvation for sodium hydroxide = -41.0 kJ/mole

Heat evolved by solvation of 3.125 moles of NaOH = Q'

Total quantity of heat is released when NaOH and HCl are mixed:

Q + Q' = -175 kJ + (-128) kJ = -303 kJ

(negative sign indicates that energy released)

303 kilo Joules is the quantity of heat is released.

i'm assuming that it's c.) red bank..

the answers would be

the first one and the second one