Write the equations that represent the first and second ionization steps for selenic acid (H2SeO4) in water. (Use H3O instead of H .) First ionization step: H2O(l) Second ionization step: H2O(l)

First ionization step:

H₂SeO₄(aq) + H₂O(l)  →  H₃O⁺(aq) + HSeO₄⁻(aq)

Second ionization step:

HSeO₄⁻(aq) + H₂O(l)  →  H₃O⁺(aq) + SeO₄⁻²(aq)

Explanation:

Selenic acid is a dyprotic and a strong acid with the formula: H₂SeO₄.

When it reacts to water, it release two protons in two ionizations.

Finally it gives hydronium to the medium.

H₂SeO₄(aq) + H₂O(l)  →  H₃O⁺(aq) + HSeO₄⁻(aq)

HSeO₄⁻(aq) + H₂O(l)  →  H₃O⁺(aq) + SeO₄⁻²(aq)

i believe the answer is three water molecules