Solve the equation for n 0.0092=0.608 x (n/84.01)+n/52.5

Explanation:

1. Rewrite the equation in a more appropriate format for a better understanding:

2. Multiply the whole equation (both sides) by 84.01 × 52.5 to eliminate the denominators:

3. Do the operations:

4. Add like terms:

5. Divide both sides by 115.93:

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally