The combustion of pentane produces heat according to the following thermochemical equation. C5H12(l) + 8O2(g) → 5CO2(g) + 6H2O(l) ΔH°rxn= –3510 kJ/mol How many grams of CO2 is produced per 2.50 × 103 kJ of heat released?\

156.68 grams of carbon dioxide is produced per kJ of heat released.

Explanation:

Amount of energy produced = Q =

Let the moles of pentane burnt to produce Q energy be n.

According to reaction, 1 mole of pentane gives 5 moles of carbon dioxide gas, then 0.7122 moles of pentane will give :

Mass of 3.561 moles of carbon dioxide gas :

3.561 mol × 44 g/mol = 156.68 g

156.68 grams of carbon dioxide is produced per kJ of heat released.

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