What is the molality of a solution made by dissolving 5.2 g of NaCl in 100 g of water?

The molality is 0,89

Explanation:

A molal solution indicates the moles of solute in 1 kg of solvent (1000 g). First, we calculate the weight of 1 mol of NaCl:

Weight NaCl= Weight Na + Weight Cl=23g + 35,5 g=58,5 g/mol

58,5 g1 mol NaCl

5,2 gx=(5,2 gx1 mol NaCl)/58,5 g=0,089 mol NaCl

100g water0,089 mol NaCl

1000g waterx=(1000g waterx0,089 mol NaCl)/100 g water

x=0,89 mol NaCl> 0,89 m

in chemistry, adhesion and cohesion are attractive forces that exist between molecules. they hold the molecules together from each other. they are different in that adhesive force exists between molecules of different substance while cohesive force happens between molecules of same substance.

adhesion between water and glass causes water molecules at the edge of water and glass interface to climb up the wall in a narrow glass tube. this is called capillary action. cohesion is what gives glass its shape and causes water to form a droplet.

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