Chemistry, 23.03.2020 22:24, icario4710

See if you can balance the unbalanced reaction that appears on the screen for the combustion of methane:

CH4 + O2 > CO2 + H20

and for the partial combustion of methane:

CH4 + O2 > CO2 + CO + H20 + C

Notice that the partial combustion of methane is responsible for the production of an extremely dangerous gas. What gas is it and why is it so dangerous?

Answers: 2

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Answers

answered: gaelle90701

The answer to your question is below

Explanation:

Unbalanced chemical reaction

CH₄ + O₂ ⇒ CO₂ + H₂O

Reactants Elements Products

1 C 1

4 H 2

2 O 3

Balanced chemical reaction

CH₄ + 2O₂ ⇒ CO₂ + 2H₂O

Reactants Elements Products

1 C 1

4 H 4

2 O 4

Unbalanced chemical reaction

CH₄ + O₂ ⇒ CO₂ + CO + H₂O + C

Reactants Elements Products

1 C 3

4 H 2

2 O 4

Balanced chemical reaction

6CH₄ + 9O₂ ⇒ 2CO₂ + 2CO + 12H₂O + 2C

Reactants Elements Products

6 C 6

24 H 24

18 O 18

The partial combustion of Methane produces CO (carbon monoxide) is a highly poisonous, odorless, colorless and tasteless gas. When it combines with hemoglobin, hemoglobin becomes ineffective for delivering oxygen to tissues.

answered: Guest

$\frac{239}{94}pu+\frac{1}{0}n ====> \frac{y}{z}x+\frac{134}{54}xe+3\frac{1}{0}$

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137 subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54 subtract 54 from both sides.

40 = z

answer

$\frac{103}{40}x=\frac{103}{40}zr$

answered: Guest

c. is the answer

by love gaming

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See if you can balance the unbalanced reaction that appears on the screen for the combustion of meth...