Chemistry, 23.03.2020 20:26, kcutler8603

Stearic acid, fatty acid commonly found in animal fat has a condensed Chemical formula CH3(CH2)16COOH. It is a common component of soaps and detergents. Which of the following statements is false?
A The -COOH group would experience hydrogen bonding with water
B The long alkane ''tail" CH3(CH2)16 -, is hydrophbic
C Stearic acid and water are probably miscible
D Stearic acid would probably dissolve in non polar solvents such as hexane C6H14
E Stearic acid contains hydrophobic regions

Answers: 3

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answered: Milan1025

The correct answer is option C.

Explanation:

A. The -COOH group would experience hydrogen bonding with water.

The statement is true because , double bonded oxygen atom of carboxylic group interacts with hydrogen atom of water molecule and oxygen atom of water molecule is in same interaction with hydrogen atom of carboxylic acid.

B. The long alkane ''tail" $CH_3(CH_2)_{16} -$ , is hydrophobic.

The statement is true because , region which do not interacts with water molecule is termed as hydrophobic region and region which do interacts with water molecule is termed as hydrophilic region. Generally ,alkanes are are hydrophobic in nature so is the alkane chain in stearic acid.

C. Stearic acid and water are probably miscible.

The statement is false because of higher hydrophobic region the interaction between the acid molecules and water molecules results in immiscibility.

D. Stearic acid would probably dissolve in non polar solvents such as hexane $C_6H_{14}$ .

The statement is true because of hydrophobic part in stearic acid is larger so that is why it get easily dissolve in non polar solvents.

E. Stearic acid contains hydrophobic regions

The statement is true because of higher hydrophobic region due to which they easily get dissolved in organic and non polar solvents.

answered: Guest

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons

answered: Guest

For cyclohexane compounds drawn in a chair conformation: -axial bonds are vertical -equatorial bonds are parallel to two bonds within the ring. thus, as i assume the chair conformation is drawn: -the x group is in an axial position, as are the five other vertical bonds. -three axial bonds are on the top face of the ring -the other three axial bonds are on the bottom face the position of the second substituent on each ring carbon is equatorial. gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other. drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1. click this link and watch some academic videos that may you more understand the topic