Calculate the pH of a solution prepared by dissolving .37 mol of formic acid and .23 mol of sodium formate in water sufficient to yield 1.00 L of solution. The Ka of Formica acid is 1.77x10^-4.
And please show how to do it.

A) 2.1
B) 10.46
C)3.55
D)2.31
E)3.95

the ozone layer acts as a filter for the shorter wavelength and highly hazardous ultraviolet radiation (uvr) from the sun, protecting life on earth from its potentially harmful effects. when the sky is clear, there is an inverse relationship between stratospheric ozone and solar uvr measured at the earth's surface.

може ли да зареждате повече информация, моля

the answer is c i took the test

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally