74. What is the empirical formula for a compound which contains 73.9%Hg and 26.1% Cl

Hg is the empirical formula for a compound which contains 73.9%Hg and 26.1% Cl.

Explanation:

given that:

Hg = 73.9 %  atomic mass of Hg= 200.59

Cl = 26.1        atomic mass of Cl= 35

let us assume that this percentage is in 100 grams.

number of moles =

number of moles of Hg =

                                        = 0.363 moles

number of moles of Cl =

                                      = 0.735 moles

molar ratio of  Cl and Hg  =

                                        =  2:1

In emperical formula first cation then anion is written.

We can see that Cl is twice the number of Hg. So the formula is

Hg is the empirical formula

"the periodic table is arranged in order of atomic number."