Chemistry
Chemistry, 23.03.2020 03:38, masaiyahrhemanow

N2(g) + 2 O2(g) 2 NO2(g) ΔH = +66.4 kJ

What would the enthalpy change for the following reaction be?

4 NO2(g) 2 N2(g) + 4 O2(g) ΔH = ???

a. +66.4 kJ
b. -66.4 kJ
c. +132.8 kJ
d. -132.8 kJ
e. -33.4 kJ

answer
Answers: 1

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N2(g) + 2 O2(g) 2 NO2(g) ΔH = +66.4 kJ

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