In the following chemical reaction the oxidizing agent is
5H2O2 + 2MnO4– + 6H+ → 2Mn2+ + 8H2O + 5O2

From the following chemical reaction, the oxidizing agent is MnO4– .

An oxidation reaction is a type of chemical reaction which occurs when oxygen is added to or hydrogen is removed from an element, molecule or a compound.

Oxidizing agents are those elements or ions that receives or accepts electron during a chemical reaction.

How to identify an oxidizing agent in a chemical reaction:

From the above equation, MnO4– gained electron from -1 to +1 through the release of its oxygen.

Therefore, the oxidizing agent is MnO4– .

Learn more about oxidizing agents here:

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Explanation:

The oxidizing agent in a chemical reaction is the reactant that undergoes chemical reduction. An oxidizing agent is an electron pair acceptor which causes a co-reactant to be oxidized in a reaction.

In the given reaction MnO₄⁻ is the oxidizing agent.

One of the ways to spot an oxidizing agent is that the number of electronegative atoms around it reduces considerably.

Also we see that the oxidation number of Mn reduces in moving from reactants to products.

where's the diagram?

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