Ordena de mayor a menor según sus radios iónicos a los siguientes iones:

a) Na + 1 , Mg + 2 , F – 1 y Cl – 1

b) Li + 1 , Be + 2 , O – 2 y S – 2

c) Na + 1 , S – 2 , Cl – 1 y K + 1

The correct order of the elements, taking into account their ionic radius from highest to lowest, is:

a) Cl⁻¹ > F⁻¹ > Na⁺¹ > Mg⁺²

b) S⁻² > O⁻² > Li⁺¹ > Be⁺²

c) S⁻² > Cl⁻¹ > K⁺¹ > Na⁺¹

Explanation:

In ions the ionic radius is determined by the amount of electrons an element gains or loses to become an ion.  The more negative an ion is, the greater its ionic radius.

As a rule, anions (negative charge) have a larger ionic radius than cations (positive charge), because the loss of electrons means a contraction of the ionic radius, while the gain of electrons means a greater radius.

To determine which ionic radius is greater in anions or cations with the same charge, it must be considered that in the periodic table the ionic radius increases from top to bottom and from right to left.

Learn more:

Ionic radius example

idk i’m struggling too