Plz anybody could answer it

2.88 x 10⁻¹³mol

Explanation:

Given parameters:

Concentration of chlorophyll in seawater = 1.2nanomoldm⁻³

Volume of seawater  = 1cm³

Unknown:

Mass of magnesium present = ?

Solution:

To solve this problem, we need to obtain the number of moles of the solute in the sea water.

Since we have been given the value of concentration, our work is easy to do;

           Number of moles  = concentration  x volume

Let us convert the given volume to dm³;

                1000cm³ = 1dm³

                    1cm³ is  = 0.001dm³

      Number of moles  = 1.2nanomoldm⁻³ x 0.001dm³

                                       = 1.2 x 10⁻³ nanomol

                                       = 1.2 x 10⁻³ x 10⁻⁹mol

                                      = 1.2 x 10⁻¹²mol

Formula of the compound:

             C₅₅ H₇₇ Mg N₄ O₅

        1 mole of C₅₅ H₇₇ Mg N₄ O₅ contains 1 mole of Mg

       1.2 x 10⁻¹²mol of C₅₅ H₇₇ Mg N₄ O₅ will contain  1.2 x 10⁻¹²mol of Mg

Since we now know the number of moles of Mg;

          Mass  = number of moles x molar mass

                      = 1.2 x 10⁻¹²  x 24

                      = 28.8 x 10⁻¹²mol

                       = 2.88 x 10⁻¹³mol

the dissolution of polymer can be thermodynamically described in 2 steps.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.