Perform the following heat calculations. You must show all work and include units on answers.

The specific heat capacity of water is 4.184 J/g°C. How much heat is required to heat 500.0 g of water from 50.0°C to 100.°C?

A 45.4 g sample of lithium is cooled from 250.0°C to 25.0°C. The specific heat capacity of lithium is 3.56 J/g°C, what amount of heat is released?

104600 Joules; 36365.4 Joules

Explanation:

A) For question 1

The quantity of Heat Energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since, M = 500.0 g

C = 4.184 J/g°C

Φ = 100°C - 50°C = 50°C

Q = 500g x 4.184J/g°C x 50°C

Q= 104600 Joules

Thus, it takes 104600 Joules of heat energy to heat the water

B) For question 2

The quantity of Heat Energy (Q) released on cooling a heated substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since, M = 45.4 g

C = 3.56 J/g°C,

Φ = 250°C - 25°C = 225°C

Q = 45.4g x 3.56J/g°C x 225°C

Q= 36365.4 Joules

Thus, 36365.4 Joules of heat energy is released when the lithium is cooled.

the mass of the cathode increases because ions from the solution get reduced to atoms and become part of the cathode.

explanation:

subscribe to my yt channel yoongi jmz

follow my insta yoongi_jams

stan bts