Calculate the molecular formulas of the compounds having the following empirical formulas and molar masses: C₂H₅, 58 g/mol; CH, 78 g/mol; and HgCl, 236.1 g/mol.

C₂H₅ would be C₄H₁₀

CH would be C₆H₆

HgCl would be HgCl

Explanation:

C₂H₅ = C₄H₁₀ (2 times the mass of C₂H₅)

CH = C₆H₆ (6 times the mass of CH)

HgCl = HgCl (same mass)

do u have any choices to choose from ? ?

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the   per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:                   1 - α               α               α           = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

=  

or,

or,   = (at v = 1l)

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:               (1 - α)/0.5           α/0.5         α/0.5       = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

or,  

=  

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%