Please help with this chemistry question, image attached.

a. Sally did not take account the atoms of the compounds, because she only summed Al + O and in the oxide, we have 2 mol of Al and 3 mol of O

b. The conversion factor that Jacob did, was wrong.

Moles must be divided by moles, so they can be cancelled. The correct conversion factor is:

9.45 mol . 102 g / 1 mol = 963.9 g

Explanation:

Al₂O₃ → Aluminum oxide

We determine the molar mass:

Molar mass Al . 2 + Molar mass O . 3

27 g/mol . 2 + 16 g/mol . 3 = 102 g/mol

a. Sally did not take account the atoms of the compounds, because she only summed Al + O and in the oxide, we have 2 mol of Al and 3 mol of O

b. The conversion factor that Jacob did, was wrong.

Moles must be divided by moles, so they can be cancelled. The correct conversion factor is:

9.45 mol . 102 g / 1 mol = 963.9 g

the answer is alpha particles hope i you

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