The above shows balloon full of gas which has a volume of 120 mL at 300° kelvin swimming pressure remains constant what is the volume of the balloon if the temperature of the gas increases to 320° kelvin

124.18cm³ or 124.18mL

Explanation:

From Charles law, the volume of a given mass of gas is inversely proportional to it Temperature provided pressure remains constant.

V1 = 120mL = 120cm³

T1 = 300°C = (300 + 273.15)K = 573.15K

T2 = 320°C = (320 + 273.15)K = 593.15K

V2 = ?

V1 / T1 = V2 / T2

V2 = (V1 * T2) / T1

V2 = (120 * 593.15) / 573.15

V2 = 124.18cm³

V2 = 124.18mL

Note 1mL = 1*10^-3L = 1cm³

answeridentity;