The base protonation constant Kb of allantoin (C4H4N3O3NH2) is ×9.1210−6. Calculate the pH of a 1.1M solution of allantoin at 25°C. Round your answer to 1 decimal pl

pH= 11.5

Explanation:

To the calculation of the pH value, we need to write the ionization equation first. Then using the ICE table and the information given by the problem we can set up the problem:

I                  1.1 M                                                Zero                             Zero              

C                   -X                                                   +X                                 +X

E                  1.1-X                                                   X                                   X

As next step, using the equilibrium expression for Kb we can replace the terms find in the ICE table and then solve for X, so:

With the value of X we can find the pOH (lets remember that X is the concentration of OH-), so:

Finally, we can find the pH value with the equation:

The 1.1 M allantoin solution have a pH value of 11.5

108

explanation:

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both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .