For the question(s) that follow, consider the following equation. Mg3N2(s) + 6H2O(l) → 3Mg (OH)2(s) + 2NH3(g) What is the correct form of the conversion factor needed to convert the number of moles of H2O to the number of moles of NH3 produced?

2/6

Explanation:

In a balanced chemical equation as:

aA + bB → cC + dD

Where coefficients of reaction relates the number of moles of substances that are involved in the reaction. In the reaction:

Mg₃N₂(s) + 6H₂O(l) → 3Mg(OH)₂(s) + 2NH₃(g)

Per mole of Mg₃N₂(s) and per 6 moles of H₂O you will produce 3 moles of Mg(OH)₂(s) and 2 moles of NH₃(g).

To convert moles of H₂O to moles of NH₃ you can use:

X moles of H₂O ₓ (2 moles NH₃ / 6 moles of H₂O)

That means conversion factor to convert the number of moles of water to number of moles of ammonia is 2/6.

-It is important to say that obtention of conversion factor requires, in the first, the balanced chemical equation-

I hope it helps!

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.