An aqueous solution of calcium hydroxide is standardized by titration with a 0.164 M solution of hydroiodic acid. If 17.2 mL of base are required to neutralize 14.7 mL of the acid, what is the molarity of the calcium hydroxide solution?

0.07 M

Explanation:

We have to start with the reaction between the Calcium hydroxide and the Hydroiodic acid:

Then we have to balance the reaction:

We have to keep in mind that we have to do use the volume in "L" units (14.7 mL= 0.0147L). When we plug the values into the equation we will get:

Now, we have to use the information from the balanced reaction to finding the moles of Calcium hydroxide. When we check the reaction we found a molar ratio of 1:2 ( 1 mol of : 2 mol of  ). With this molar ratio, we can find the moles of .

Finally, to find the molarity we have to divide the moles of and the volume of in liters (17.2 mL=0.0172L) so:

The molarity of is 0.07M.

*tilts head* sounds more like a statement