Find the [OH^-1] if the pH is 11.7
A) 1.0 x 10^-12 M
B) 2.9 x 10^-11 M
C) 1.5 x 10^-12 M
D) 2.0 x 10^12 M

None of the options are correct.

The answer to the question is 5.01x10^-3M

Explanation:

The following were obtained from the question:

pH = 11.7

Recall: pH + pOH = 14

11.7 + pOH = 14

pOH = 14 — 11.7

pOH = 2.3

Now we can obtain the [OH^-1] as follows:

pOH = —Log [OH^-1]

pOH = 2.3

2.3 = —Log [OH^-1]

—2.3 = Log [OH^-1]

Take the anti-log of —2.3

[OH^-1] = 5.01x10^-3M

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