On the lab bench there are four solutions; one is yellow and the other three are colorless. Which of the following four transition metal compounds is likely the yellow solution? On the lab bench there are four solutions; one is yellow and the other three are colorless. Which of the following four transition metal compounds is likely the yellow solution? Why?

[Cr(NH3)6]Cl3

K[V(C2O4)3]

[Ti(H2O)6]Cl4

[Zn(en)2]Br2

[Cr(NH₃)₆]Cl₃

Explanation:

The transition metal compound most likely to form a yellow solution is the complex of [Cr(NH₃)₆]Cl₃,

Transition metals belongs to the d-block on the periodic table. They are made up of atoms whose d-subshell are partially or fully filled.

Most these elements have variable oxidation states and exhibits colored properties. They display a wide range of colors .

[Cr(NH₃)₆]Cl₃ is a complex that absorbs other wavelength of light but reflects yellow light making it visibly yellow.

The colors originates from the transition of electrons through electronic orbitals and thereby giving off corresponding light that we visibly observe.

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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