Chemistry, 17.03.2020 04:32, hrijaymadathil
Enter your answer in the provided box. Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Determine ΔHrxn for C(diamond) → C(graphite) with equations from the following list: (1) C(diamond) + O2(g) → CO2(g) ΔH = −395.4 kJ (2) 2 CO2(g) → 2 CO(g) + O2(g) ΔH = 566.0 kJ (3) C(graphite) + O2(g) → CO2(g) ΔH = −393.5 kJ (4) 2 CO(g) → C(graphite) + CO2(g) ΔH = −172.5 kJ
Answers: 3
Chemistry, 22.06.2019 12:00, Unknowndragon42
Consider the following reaction at equilibrium. 2co2 (g) 2co (g) + o2 (g) h° = -514 kj le châtelier's principle predicts that the equilibrium partial pressure of co (g) can be maximized by carrying out the reaction a. at high temperature and high pressure b. at high temperature and low pressure c. at low temperature and low pressure d. at low temperature and high pressure e. in the presence of solid carbon
Answers: 2
Chemistry, 22.06.2019 16:50, shaylawaldo11
Which element is least likely to undergo a chemical reaction
Answers: 3
Enter your answer in the provided box. Diamond and graphite are two crystalline forms of carbon. At...
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