When a 120g sample of aluminum absorbs 9612 J of energy its temperature increases from 298K to 388K. Find the specific heat of the aluminum.

Specific heat of Aluminium is 0.89 g/J

Explanation:

Step  1 :

Specific heat of a substance is the energy absorbed by a substance of unit mass when its temperature increases by one degree.

Energy Absorbed = Specific Heat * Mass of the substance * Temperature Difference

Step  2 :

It is given that 120 g sample absorbs 9612 J energy when the temperature increases from 298K to 388K.

Temperature Difference = 388 K - 298 K = 90 K

Step  3:

Specific Heat = (Energy Absorbed) ÷ (Mass of the substance * Temperature Difference)

Specific Heat = 9612 ÷  (120 * 90) = 0.89 grams / Joule

Step  4:

Specific heat of Aluminium is 0.89 g/J

n has four pairs of electrons in the valence shell, electrons repel one another ,n has 7 protons in its nucleus, and since n has 7 protons, it must fill the second shell, giving it 4 pairs of electrons. the electrons form 3 bonds and 1 lone pair of electrons. each pair of electrons repels the other pairs, so they are equally far apart.

so all of the above