Calculate the volume of 1M NaOH required to neutralize 200 cc of 2M HCI. What mass of sodium
chloride are produced from the neutralization reaction?
[1+1+1+2]

Make me clear with tail question.
Give as much detail explanation as possible.
Please

NaOH+HCl-> NaCl+H2O

1 mole of NaOH

1 mole of HCl.

To calculate volume of NaOH

CaVa/CbVb= Na/Nb

Where Ca=2M

Cb=1M

Va=200cm³

Vb=xcm³

Substitute into the equation.

2×200/1×Vb=1/1

400/Vb=1/1

Cross multiply

Vb×1=400×1

Vb=400cm³

To calculate the mass of sodium chloride, NaCl from the neutralization rxn.

Mole of NaCl=1

Molar mass of NaCl= 23+35.5=58.5

Mass=xgrammes.

Mass of NaCl=Number of moles × Molar mass.

Substitute

Mass of NaCl= 1×58.5

=58.5g

This is what I could come up with.

water is used to store them because it would keep the radiation from getting out in the open and causing harm to the workers

your answer would be “dry”