A Assuming the reaction is first order in sucrose, determine the mass of sucrose that is hydrolyzed when 2.50 LL of a 0.180 MM sucrose solution is allowed to react for 200 minmin .

The question is incomplete, here is the complete question:

The hydrolysis of sucrose into glucose and fructose in acidic water has a rate constant of 1.8×10⁻⁴ s⁻¹ at 25°C. Assuming the reaction is first order in sucrose, determine the mass of sucrose that is hydrolyzed when 2.65 L of a 0.120 M sucrose solution is allowed to react for 200 min.

The mass of sucrose solution left is 12.56 grams

Explanation:

Molarity is calculated by using the equation:

Molarity of sucrose solution = 0.120 M

Volume of solution = 2.65 L

Rate law expression for first order kinetics is given by the equation:

where,

k = rate constant =

t = time taken for decay process = 200 min = (200 × 60) = 12000 seconds

= initial amount of the sample = 0.318 moles

[A] = amount left after decay process = ?

Putting values in above equation, we get:

To calculate the mass from given number of moles, we use the equation:

Moles of sucrose = 0.0367 moles

Molar mass of sucrose = 342.3 g/mol

Putting values in above equation, we get:

Hence, the mass of sucrose solution left is 12.56 grams

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation:

a is the correct answer