Two hypothetical ionic compounds are discovered with the chemical formulas XCl2 and YCl2, where X and Y represent symbols of the imaginary elements. Chemical analysis of the two compounds reveals that 0.25 mol XCl2 has a mass of 100.0 g and 0.50 mol YCl2 has a mass of 125.0 g. a. what are the molar masses of XCl2 and YCl2? b. If you had 1.0-mol samples of XCl2 and YCl2, how would the number of chloride ions compare? c. If you had 1.0-mol samples of XCl2 and YCl2, how would the masses of elements X and Y compare? d. what is the mass of chloride ions present in 1.0 mol XCl2 and 1.0 mol YCl2? e. What are the molar masses of elements X and Y? f. How many moles of X ions and chloride ions would be present in a 200.0 g sample of XCl2? g. How many grams of Y ions would be present in a 250.0 g sample of YCl2? h. What would be the molar mass of the compound YBr3?

THE MOLAR MASS OF XCL2 IS 400 g/mol

THE MOLAR MASS OF YCL2 IS 250 g/mol.

Explanation:

We calculate the molar mass of XCL2 and YCL2 by bringing to mind the formula for molar mass when mass and amount or number of moles of the substance is given.

Number of moles = mass / molar mass

Molar mass = mass / number of moles.

For XCL2,

mass = 100 g

number of mole = 0.25 mol

So therefore, molar mass = mass / number of moles

Molar mass = 100 g / 0.25 mol

Molar mass = 400 g/mol.

For YCL2,

mass = 125 g

number of mole = 0.50 mol

Molar mass = 125 g / 0.50 mol

Molar mass = 250 g/mol.

So therefore, the molar mass of XCL2 and YCL2 IS 400 g/mol and 250 g/mol respectively.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer