What is the percent yield of aluminum phosphate if a solution containing 33.4 g of sodium phosphate produced 19.6 g of aluminum phosphate when reacted with excess aluminum chloride in solution

The percent yield of aluminium phosphate in the reaction is 78.78 %

Explanation:

To calculate the number of moles, we use the equation:

    .....(1)

Given mass of sodium phosphate = 33.4 g

Molar mass of sodium phosphate = 164 g/mol

Putting values in equation 1, we get:

The chemical equation for the reaction of sodium phosphate and aluminium chloride is:

By Stoichiometry of the reaction:

1 mole of sodium phosphate produces 1 mole of aluminium phosphate

So, 0.204 moles of sodium phosphate will produce = moles of aluminium phosphate

Molar mass of aluminium phosphate = 122 g/mol

Moles of aluminium phosphate = 0.204 moles

Putting values in equation 1, we get:

Experimental yield of aluminium phosphate = 19.6 g

Theoretical yield of aluminium phosphate = 24.88 g

Putting values in above equation, we get:

Hence, the percent yield of aluminium phosphate in the reaction is 78.78 %

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of carbon is as shown here in the image.

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.