A 63 g piece of magnesium absorbs 6689 J of heat. The final temperature is 663°C. What was the initial temperature? The specific heat of magnesium is 1.023 J/g degrees Celsius.

The initial temperature was 559.21 °C

Explanation:

Mass of Magnesium(M) =63 gm

Heat absorbed (Q) = 6689 J

Specific Heat (S) = 1.023 J/gm°C

Let, Initial Temperature  = °C

Final Temperature () = 663°C

We know that, Q = M×S( - )

              6689 = 63 × 1.023 × ( 663 - )

              663 - = 6689 ÷ ( 63 × 1.023)  

              = 663 - 103.79

                  = 559.21 °C

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