Predict the direction in which the equilibrium will lie for the reaction H2SO3(aq) + HCO3- (aq) <> HSO3-(aq) + H2CO3(aq). Given: Ka1(H2SO3) = 1 x 10-2; Ka1(H2CO3) = 4.2 x 10-7

Explanation:

As we know that is a strong acid as compared to carbonic acid. As a result, sulfurous acid () is a stronger acid and it will over come carbonic acid.

In a neutralization reaction, the equilibrium will favor side of weaker acids and bases in neutralization.

As of is greater than the value of .

Thus, we can conclude that the reaction equilibrium will move towards the right hand side.

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.

i think so it’s will be b yes i believe its