Calculate the volume, in liters and to the hundredths place, of a stock solution that has a concentration of 0.235 M Ca(NO3)2 and when diluted to a 0.872 L becomes 0.18 M Ca(NO3)2.

0.670L is the volume for the concentrated solution

Explanation:

There is an element that indicates the relation between Molarity of concentrated solution with Molarity of diluted solution or their volumes.

This is the dilution factor.

We can apply like this:

Molarity of concentrated / Molarity of diluted = Volume of diluted / Vol. conc.

We replace data: 0.235 M / 0.18 M = 0.872L / Volume of concentrated

1.30 = 0.872L / Volume of concentrated

Volume of concentrated = 0.872L / 1.30

Volume of concentrated = 0.670L

The volume of the stock solution = 0.053L

Explanation:

Step 1: Data given

Concentration of the stock solution = 0.235 M Ca(NO3)2

Concentration of the diluted solution =0.18 M Ca(NO3)2

Volume of the diluted solution = 0.872 L

Step 2: Calculate the volume of the stock solution

C1*V1 = C2*V2

⇒with C1 = the concentration of the stock solution = 0.235 M Ca(NO3)2

⇒with V1 = the volume of the stock solution = TO DETERMINED

⇒with C2 = the concentration of the diluted solution = 0.18 M Ca(NO3)2

⇒with V2 = the volume of the diluted solution = 0.872 L

1.5 M * V1 = 0.80 M * 0.10 L

V1 = 0.053 L

0.053 L of stock solution was used.

explanation:

a. energy is absorbed in the reaction.

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.