At -9.27 °C the pressure equilibrium constant Kp = 5.4 x 10^-5 certain reaction.

Here are some facts about the reaction:

O The constant pressure molar heat capacity Cp = 2.20 J*mol^-1*K^-1

O If the reaction is run at constant pressure, 102. kJ/mol of heat are absorbed. .

O If the reaction is run at constant pressure, the volume increases by 9.1%.

1. Using these facts, can you calculate Kp at 7.9°C?

OYes O No.

2. If you said yes, then enter your answer . Round it to 2 significant digits

Five students had to answer the question how are elements arranged in a periodic tabledamon: i think the elements are arranged by increasing massflo: i think the elements are arranged according to their properties sienna: i think the elements are arranged by when their discovers kyle: i think the elements are arranged according to how common they areglenda: i don't agree with any of themwho is right

13. calculate the initial concentration (before precipitation) of carbonate ions after the addition of each 0.05 ml of solution b to the 1.00 l beaker of solution a. divide the work among group members and write the answers in the table in model 3. assume the volume change as solution b is added is negligible. 14. notice the initial concentrations of zn2+ - and cu2+ in the table in model 3. a. explain how these were obtained from the data in model 2. b. as solution b is added and precipitates form, do these initial concentrations change? 15. use the data in model 2 to indicate the presence of precipitate (either znco3 or cuco3) after each 0.05 ml addition of solution b in model 3. 16. use the initial concentrations of carbonate ions and zinc ions to calculate the reaction quotient, qsp for the zinc carbonate scenarios in model 3. divide the work among group members and write the answers in the table in model 3. 17. use the initial concentrations of carbonate ion and copper(ii) ions to calculate the qsp for the copper(ii) carbonate scenarios in model 3. divide the work among group members and write the answers in the table in model 3.

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