The reaction between nitrogen dioxide and carbon monoxide is NO2(g)+CO(g)→NO(g)+CO2(g) The rate constant at 701 K is measured as 2.57 M−1⋅s−1 and that at 895 K is measured as 567 M−1⋅s−1. The activation energy is 1.5×102 kJ/mol. Predict the rate constant at 525 K .

Explanation:

The given data is as follows.

    ,     = 701 K

    = ?

    = 525 K

             = 150000 J / mol

Now, we will calculate rate constant as follows.

where,       R = 8.314 J per mol K

Putting the given values into the above formula as follows.

        = -8.628

    = anti ln[-8.628]

    = 0.000179

    = 0.00046

or,            =

Thus, we can conclude that the rate constant at 525 K is .

the answer is true.