Chemistry, 12.03.2020 03:51, brutalgitaffe

Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . If of water is produced from the reaction of of sulfuric acid and of sodium hydroxide, calculate the percent yield of water. Round your answer to significant figures.

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answered: rivman10

This is an incomplete question, here is a complete question.

Aqueous sulfuric acid (H₂SO₄) reacts with solid sodium hydroxide (NaOH) to produce aqueous sodium sulfate (Na₂SO₄) and liquid water (H₂O) . If 12.5 g of water is produced from the reaction of 72.6 g of sulfuric acid and 77.0 g of sodium hydroxide, calculate the percent yield of water. Round your answer in significant figures.

The percent yield of water is, 46.8 %

Explanation : Given,

Mass of H_2SO_4 = 72.6 g

Mass of NaOH = 77.0 g

Molar mass of H_2SO_4 = 98 g/mol

Molar mass of NaOH = 40 g/mol

First we have to calculate the moles of H_2SO_4 and NaOH .

$\text{Moles of }H_2SO_4=\frac{\text{Given mass }H_2SO_4}{\text{Molar mass }H_2SO_4}$

$\text{Moles of }H_2SO_4=\frac{72.6g}{98g/mol}=0.741mol$

and,

$\text{Moles of }NaOH=\frac{\text{Given mass }NaOH}{\text{Molar mass }NaOH}$

$\text{Moles of }NaOH=\frac{77.0g}{40g/mol}=1.925mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

From the balanced reaction we conclude that

As, 1 mole of H_2SO_4 react with 2 mole of NaOH

So, 0.741 moles of H_2SO_4 react with $0.741\times 2=1.482$ moles of NaOH

From this we conclude that, NaOH is an excess reagent because the given moles are greater than the required moles and H_2SO_4 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of H_2O

From the reaction, we conclude that

As, 1 mole of H_2SO_4 react to give 2 mole of H_2O

So, 0.741 moles of H_2SO_4 react to give $0.741\times 2=1.482$ moles of H_2O

Now we have to calculate the mass of H_2O

$\text{ Mass of }H_2O=\text{ Moles of }H_2O\times \text{ Molar mass of }H_2O$

Molar mass of H_2O = 18 g/mole

$\text{ Mass of }H_2O=(1.482moles)\times (18g/mole)=26.68g$

Now we have to calculate the percent yield of water.

$\text{Percent yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100$

Now put all the given values in this formula, we get:

$\text{Percent yield}=\frac{12.5g}{26.68g}\times 100=46.8\%$

Thus, the percent yield of water is, 46.8 %

answered: Guest

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.

answered: Guest

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.

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Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liqui...