Aqueous sulfuric acid will react with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . Suppose 67.7 g of sulfuric acid is mixed with 83. g of sodium hydroxide. Calculate the minimum mass of sulfuric acid that could be left over by the chemical reaction. Round your answer to significant digits.

0.00 grams

Explanation:

To calculate the moles, we use the equation:

a) moles of sulphuric acid:

b) moles of sodium hydroxide:

According to stoichiometry :

1 mole of require 2 moles of

Thus 0.69 moles of require= of

Thus is the limiting reagent as it limits the formation of product and will be completely used and NaOH is the excess reagent.

Thus sulfuric acid will not be left over by the chemical reaction.

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