This molecule can be synthesized from an alkyne anion and an alkyl bromide. However, there are two ways in which this molecule can be formed. One way uses a higher molecular weight alkyne anion (Part 1) and the other uses a lower molecular weight anion (Part 2). Draw the two versions in the boxes below. Omit spectator ions.

For Part 1: Draw the reactants (i. e., alkyne anion and alkyl bromide) needed for the pathway that uses a higher molecular weight alkyne anion:

For Part 2: Draw the reactants (i. e., alkyne anion and alkyl bromide) needed for the pathway that uses a lower molecular weight alkyne anion:

d is

108

explanation:

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i think? ?

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o