Calculate the equilibrium concentration of [N2][N2] if the initial concentrations are 2.25 MM N2N2 and 0.55 MM O2O2. (This N2/O2N2/O2 concentration ratio is the ratio found in air.)

The equilibrium concentration of N2 is 2.22765 M

Explanation:

The air pollutant NO is produced in automobile engines from the high-temperature reaction:

N2(g)+O2(g) <--> 2NO(g)  Kc=1.7 * 10^-3

Part A: Calculate the equilibrium concentration of N2 if the initial concentrations are 2.25 M N2 and 0.55 M O2. (This N2/O2 concentration ratio is the ratio found in air.)

Step 1: Data given

Initial concentration of N2 = 2.25 M

Initial concentration of O2 = 0.55M

Kc = 1.7 * 10^-3

Step 2: The initial concentrations

[N2] = 2.25 M

[O2] = 0.55 M

[NO] = 0M

Step 3: The concentrations at equilibrium

[N2] = 2.25 - x M

[O2] = 0.55 - x M

[NO] = 2x M

Step 4: Kc

Kc = 1.7 *10^-3 = (2x)² / (2.25 -x)(0.55 -x )

1.7 * 10^-3 = 4x² / (1.2375 - 2.80x  +x² )

0.0017x² - 0.00476x + 0.002104 = 4x²

3.9983x² + 0.00476x - 0.002104 = 0

x = 0.02235

[N2] = 2.25 - x M = 2.25 - 0.02235 = 2.22765 M

[O2] = 0.55 - x M = 0.55 - 0.02235 = 0.52765 M

[NO] = 2x M = 2* 0.02235 = 0.0447 M

The equilibrium concentration of N2 is 2.22765 M

your parents i think this could be it

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.