How many grams of hydrogen gas would be produced from the use of 9.5 miles of aluminum?

28.5g of H2

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

2Al + 6HCl —> 2AlCl3 + 3H2

From the balanced equation,

2moles of Al produced 3moles of H2.

Therefore, 9.5 moles of Al will produce = (9.5x3)/2 = 14.25moles of H2.

Now let us convert 14.25moles of H2 to grams as illustrated below:

Molar Mass of H2 = 2x1 = 2g/mol

Number of mole H2 = 14.25moles

Mass of H2 =?

Number of mole = Mass /Molar Mass

Mass = number of mole x molar Mass

Mass of H2 = 14.25 x 2

Mass of H2 = 28.5g

it is b that is the answer.