F 18.5 mL mL of 0.800 M HCl M HCl solution are needed to neutralize 5.00 mLmL of a household ammonia solution, what is the molar concentration of the ammonia

The molar concentration of the ammonia is 2.96 M.

Explanation:

In titration the known concentrated acid or base solution is added to unknown concentration solution until a neutral point is formed.

In titrations the formula used is

Macid x V acid = Mbase x V base

The volume must be in litre.

From the question it can be found that HCl is used to neutralize household ammonia.

Volume of HCl is 18.5 ml which is L

molarity of the HCl is given 0.8 M

Volume of the base NH3 is given 5ml which is L

Using the formula given above

Macid x V acid = Mbase x V base

Putting the values in the equation:

0.8 x 0.0185 = Mbase x 0.005

Mbase =  

  Mbase         = 2.96 M

your answer would be a. 12.5 kg