A titration of vinegar with a solution of NaOH was performed. If 3.45 mL of vinegar needs 44.0 mL of 0.140 M NaOH to reach the equivalence point in a titration, Calculate the mass of acetic acid present in the vinegar sample: mastering chemistry answers

The mass of acetic acid present in the vinegar sample is 0.370 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

Molarity of NaOH solution = 0.140 M

Volume of solution = 44.0 mL

Putting values in above equation, we get:

The chemical equation for the reaction of acetic acid and NaOH follows:

By Stoichiometry of the reaction:

1 mole of NaOH reacts with 1 mole of acetic acid

So, 0.00616 moles of NaOH will react with = of acetic acid

To calculate the number of moles, we use the equation:

Molar mass of acetic acid = 60 g/mol

Moles of acetic acid = 0.00616 moles

Putting values in above equation, we get:

Hence, the mass of acetic acid present in the vinegar sample is 0.370 grams

"record the time to complete a chemical reaction" would most likely be part of a lab procedure.

a. energy is absorbed in the reaction.

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.