The equilibrium constant, Kc , for the decomposition of COBr2 COBr2(g) ↔ CO(g) + Br2(g) is 0.190. What is Kc for the following reaction? 2CO(g) + 2Br2(g) ↔ 2COBr2(g)

27.70 is for the reaction.

Explanation:

The equilibrium constant of the reaction =

The expression of equilibrium constant is given by :

..[1]

The equilibrium constant expression for above reaction can be written as:

( from [1])

27.70 is for the reaction.

hope you got the answer

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