Or the reaction: 2X 3Y r 3Z, the combination of 2.00 moles of X with 2.00 moles of Y produces 1.75 moles of Z. What is the percent yield of this reaction

% yield = 58.33 %

Explanation:

∴ moles X = 2.00 mol

∴ moles Y = 2.00 mol

∴ moles Z = 1.75 mol = moles produced

theoretical moles:

⇒ moles Z = (2.00 mol X)*(3 mol Z/2 mol X) = 3.00 mol Z

⇒ % yield = [(1.75 mol produced)/(3.00 theoretical mol)]×100

⇒ % yield = 58.33 %

just did the assignment and the answer was #1 +2 n