Three of the primary components of air are carbon dioxide, nitrogen, and oxygen. In a sample containin a mixture of only these gases at exactly 1 atm, the partial pressures of carbon dioxide and nitrogen are given as
PCO2=0.285
torr and
PN2=593.525
torr. What is the partial pressure of oxygen?

0.675

Explanation:

im not compleeatly sure if this is right jope it helps

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole