Calculate the volume of a 0.5M solution containing 20g of NaOH

1L

Explanation:

First, let us calculate the number of mole present in 20g of NaOH. This is illustrated below:

Mass = 20g

Molar Mass of NaOH = 23 + 16 + 1 = 40g/mol

Number of mole =?

Number of mole = Mass /Molar Mass

Number of mole of NaOH = 20/40 = 0.5mol

From the question given, we obtained the following data:

Molarity = 0.5M

Mole = 0.5mole

Volume =?

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 0.5/0.5

Volume = 1L

1L

Explanation:

Molar mass of NaOH is 40g/mol

Mass given is 20g

Number of moles=mass given/molar mass

Number of moles=20/40

Number of moles=0.5 moles

Volume=molarity/number of moles

Molarity=0.5M

Volume=0.5/0.5

Volume= 1

Therefore the volume is 1L

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a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.