Consider the reaction by the following equation C2 H4 + 3O2= 2CO2+2H2O

Explanation:

The question is incomplete.

This is the complete question:

Consider the reaction by the following equation:

           C₂H₄(g) + 3O₂(g) → 2CO₂(g) + 2H₂O(g)

The volume of CO₂(g) produced at s.t.p when 0.05 moles of C₂H₄(g) was burnt in O₂(g) is

[Molar Volume of gas = 22.4dm³]

   A. 1.12dm³

   B. 2.24dm³

   C. 3.72dm³

   D. 4.48dm³

1. Write the mole ratio between CO₂(g) and C₂H₄(g)

2. Multiply the 0.05 moles of C₂H₄(g) by the mole ratio

3. Convert moles of CO₂ to volume at STP using the molar volume at STP

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation:

la respuesta es si te gusta hacer lo que siempre haces cuando nunca ves a alguien en el espejo porque sabes que no siempre están ahí.