What is the density of oxygen gas (O2) at 2.3 atmospheres and 305 Kelvin? Show all of the work used to solve this problem.

2.94g/L

Explanation:

First, let us derive an expression for the density, using the ideal gas equation:

PV = nRT (1)

V = nRT/ P (2)

Recall:

Number of mole(n) = mass(m)/Molar Mass (M)

n = m/M

Substituting the value of n into equation 2:

V = nRT/ P

V = mRT/ MP

Now Divide both side by m

V/m = RT/ MP

Inverting the above equation, we have:

m/V = MP/RT

But Density = m/V

Density = MP/RT

From the question given, we obtained the following data:

P = 2.3atm

T = 305K

Molar Mass of O2 = 16x2 = 32g/mol

R = 0.082atm.L/K /mol

Density = (32x2.3)/(0.082x305)

Density = 2.94g/L

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles