Calculate the mass of water (in g) that can be vaporized at its boiling point with 155 kJ of heat. • ΔHvap = 40.7 kJ/mol (at 100 °C) • 18.02 g H2O = 1 mol H2O

The mass of water that can be vaporized at its boiling point is 68.66 grams

Explanation:

To calculate the enthalpy change of the reaction, we use the equation:

where,

= amount of heat absorbed = 155 kJ

n = number of moles = ? moles

= enthalpy change of the reaction = 40.7 kJ/mol

Putting values in above equation, we get:

To calculate the number of moles, we use the equation:

Molar mass of water = 18.02 g/mol

Moles of water = 3.81 moles

Putting values in above equation, we get:

Hence, the mass of water that can be vaporized at its boiling point is 68.66 grams